5log1per10×3log25×4logakar3=

5log1/10 × 3log25 × 4log√3 = ?

= 4log√3 x 3log25 x 5log1/10
= 4log[tex] 3^{1/2} [/tex] x 3log[tex] 5^{2} [/tex] x 5log[tex] 10^{-1} [/tex]
= (1/2)(4log3) x (2)(3log5) x (-1)(5log10)
= [1/2 x 2 x (-1)] x 4log 3 x 3log5 x 5log10
= -1 x 4log10
= - 4log10

Yeay semoga bermanfaat^^ #cmiiw