fungsi f,didefinisikan dengan rumus.f(x)=px+q,jika f(3)=-10 dan f(-2)=0, nilai f(8)

Dik. f(x) = px + q, f(3) = -10 & f(-2) = 0.
Dit. f(8) ?

Jawab...

f(x) = px + q

f(3) = 3p + q = -10
f(-2) = -2p + q = 0
------------------------ -
@ 5p = -10
@ p = -10/5
@ p = -2

q :
3p + q = -10
3(-2) + q = -10
-6 + q = -10
q = -10 + 6
q = -4

f(8) = 8p + q
f(8) = 8(-2) + (-4)
f(8) = -16 -4
f(8) = -20

Semoga membantu.. ^_^

lebih mudah difoto daripada ditulis. angka 10 ny min ya..lupa