jika 2log 3 = x dan 3log 7 = y maka 3log14 =....?

→ ²log 3 = x
→ ³log 7 = y

³log 14
= ³log(7 x 2)
= ³log 7 + ³log 2
= y + 1/(²log 3)
= y + 1/x

2 log 3 = x , 3log7 = y, 3 log 14 = ?
3 log 14 = 3 log 7 x 2
= 3 log 7 + 3 log 2
= 3 log 7 + 1 / 2log3
= y + 1/x = 1/x + y

sifat"
a log b = 1 / b log a
a log b.c = a log b + a log c