tentukan pertidaksamaan dari nilai mutlak 1. 0 < |x-3| ≤ 3 2. |2x+1| < |2x-3| 3. |x-17| ≤ |7x-5|

1. |x-3|<=3
-3<=x-3<=3
0<=x<=6

2. |2x+1|<|2x-3|
(2x+1)^2<(2x-3)^2
4x^2 + 4x +1 < 4x^2 -12x +9
16x<8
x<2

3. |x-17|<=|7x-5|
(x-17)^2<=(7x-5)^2
x^2-34x+289<=49x^2-70x+25
48x^2-36x-264>=0
12x^2-9x-66>=0
(x+2)(12x-33)>=0
x<=-2 atau x>=33/12