Integral (x+1)(x-2)/√x dx adalah

^ tanda pangkat
dijabarin dulu
(x + 1)(x - 2) / √x
= (x² - x - 2) / x^½
= x^(2-½) - x^(1-½) - 2x^(-½)
= x^3/2 - x^½ - 2x^-½
jadinya
integral (x^3/2 - x^½ - 2x^-½) dx
= (1/(3/2+1))x^(3/2+1) - (1/(1+½))x^(1+½) - (2/(-½+1))x^(-½+1) + C
= (1/(5/2))x^5/2 - (1/(3/2))x^3/2 - (2/(-½))x^½ + C
= (2/5)x^5/2 - (2/3)x^3/2 + 4x^½ + C
= (2/5)x²√x - (2/3)x√x + 4√x + C
= {(2/5)x² - (2/3)x + 4}√x + C