jika daerah asal{6,8,10,12} dengan rumus fungsif(x)=3x-4tentukan f(6),f(8),f(10),f(12)

rumus fungsi f(x) = 3x-4
f(6) = 3(6)-4 = 14
f(8)= 3(8)-4 = 20
f(10) = 3(10)-4 =26
f(12) = 3(12)-4 = 32

f(x) = 3x-4
f(6) = 3.6-4 = 18-4 = 14
f(8) = 3.8-4 = 24-4 = 20
f(10) = 3.10-4 = 30-4 = 26
f(12) = 3.12-4 = 36-4 = 32
semoga membantu ya.. ^_^