diketahui log2=0,301 log3=0,477 log5=0,699 tentukan log120

log 120
= log (2^3 × 3 × 5)
= log 2^3 + log 3 + log 5
= 3 log 2 + 0,477 + 0,699
= 3 × 0,301 + 1,176
= 0,903 + 1,176
= 2,079

log 120 = log 2³ + log 5 + log 3
log 120 = 3 log 2 + log 5 +log 3
log 120 = 3(0,301) + 0,699 + 0,477
log 120 = 0,903 + 0,699 + 0,477
log 120 = 2,079