Jika f (x) =4x3 + 3x2 - 5 carilah f(x)dx

f(x)=4x^3 + 3x^2 - 5
ditanya f(x)dx ...?
f(x)dx = ((4x^3+1)/3+1) + ((3x^2+1)/2+1) - 5x +C
f(x)dx = (4x^4)/4 + (3x^3)/3 - 5x + C
f(x)dx = x^4 + x^3 - 5x + C

ket : ^ = pangkat