Matematika

Pertanyaan

Nilai dari 8 log akar 27× 9 log 32

1 Jawaban

  • LOgarITma

    8'log √27 × 9'log 32
    = (2^3)'log 3^(3/2) × (3^2)'log 2^5
    = (3/2)/3 . 2'log 3 × (5/2) . 3'log 2
    = 1/2 . 5/2 . 2'log 3 . 3'log 2
    = 5/4 . 1
    = 5/4

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