Matematika

Pertanyaan

dalam ∆PQR, ST// QR. panjang pr=12, tr=4cm, sq=6cm, dan st=10cm hitunglah panjang pt, qr, ps

1 Jawaban

  • ∆PQR
    ST // QR

    ST/QR = PT/PR = PS/PQ

    PT = PR - TR = 12 - 4 = 8 cm

    ST/QR = PT/PR
    10/QR = 8/12
    QR = 12 × 10/8
    QR = 15 cm

    PS/PQ = PT/PR
    PS/PQ = PT/PR
    PS/PQ = 8/12
    PS/(PS + SQ) = 2/3
    PS/(PS + 6) = 2/3
    Kalikan silang
    3PS = 2PS + 12
    3PS - 2PS = 12
    PS = 12 cm

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