TOLONG jAWAB YA!!!! g(x)=xkuadrat + ax +b,jika g(-2)=5 g(1)=5 tentukan: a. nilai a&b b. bentuk fungsi c. nilai g(3)

g(x)=x^2+ax+b

g(-2)=(-2)^2+a•(-2)+b
5=(-2)^2+a•(-2)+b
5=4-2a+b
1=-2a+b

g(1)=(1)^2+a•1+b
5=(1)^2+a•1+b
4=a+b

-2a+b=1
a+b=4
---------- -
-3a=-3
a=1
b=3

Bentuk fungsi g(x)=x^2+x+3
Dan nilai dari g(3)=(3)^2+3+3=9+6=15

x² + ax + b

g(-2) => (-2)² + (-2)a + b = 5
g(-2) => 4 - 2a + b = 5 <======> -2a + b = 1

g(1) => 1² + 1a + b =5
g(1) => 1 + a + b = 5 <=======> a + b = 4

-2a + b = 1
a+ b = 4  
-3a = -3
a = 1

a+b = 4
1+b =4
b = 3

g(x) = x² + x + 3

g(3) = 3² + 3 + 3
g(3) = 9 + 6 <=> 15