Tentukan nilai suku ke 6 dari barisan geometri 243,81,27,9

a = 243
r = 81 / 243 = 1/3
Un = a.r^(n-1)
U6 = 243. (1/3)^5
      = 243 x 1/243
      = 1

Un = ar^(n-1)
a = 243
r = 81/243 = 1/3

U6 = ar^(6-1)
U6 = 243 . (1/3)^5
U6 = 243 . 1/243
U6 = 243/243
U6 = 1