Matematika

Pertanyaan

garis 7x + 2y = -13 dan 8x - 3y = -36 berpotongan di titik (p,q+1). Nilai p-q = ...

1 Jawaban

  • 7x + 2y = -13  (x3)
    8x - 3y = -36   (x2)
    --------------------------
    21x + 6y = -39
    16x - 6y = -72
    -------------------------- +
    37x = -111
    x = -111 / 37
    x = -3

    7x + 2y = -13
    7(-3) + 2y = -13
    -21 + 2y = -13
    2y = -13 + 21
    2y = 8
    y = 4

    titik potongnya (p, q+1) = (-3, 4)
    p = x
    p = -3

    q + 1 = y
    q + 1 = 4
    q = 4 - 1
    q = 3

    nilai p - q = -3 - 3 = -6

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