tolong bantuin jawab ya:))

kerucut
Tinggi kerucut= t= 15cm
jarijari = r= 8cm
panjang garis pelukis =
s²= t² + r²
= 15²+8²
= 225 + 64
s= √288
s= 17 cm
luas selimut kerucut= πrs
= 3,14×8×17
= 427,04 cm²
tabung
tinggi tabung = t= 20cm
jari-jari =r=1/2 d = 8 cm
luas selimut tabung = 2πrt
= 2×3,14×8×20
= 6,28 ×160
= 1000,48 cm²
a. luas sisi bangun
= luas tabung + luas kerucut
=[2πr(r+t) ]+[ πr(r+s)]
= [2×3,14×8(8+20)] +[3,14× 8(8+17)]
= [50,24×28] +[25,12×25]
= 1406,76 + 628
=2034,76 cm²
b. volume tabung + volume kerucut
= πr²t + 1/3πr²t
= ( 3,14 × 8²×20)+(1/3×3,14×8²×15)
= 4019,2 + 1004,8
= 5024 cm³