jika. rumus fungsi 5-3xdengan daerah asal{-3,-2,-1,0,1,2,3,4} tentukan f(-3) f(-2) f(-1) f(0) f(1) f(2) f(3) f(4)

f(-3)=5-3(-3)
=14
f(-2)=11
f(-1)=8
f(0)=5
f(1)=2
f()2= -1
f(3)=-4
f(4)=-7
coba cek lagi ya.. mana tau salah

f(x) = 5 - 3x
f(-3) = 5 - 3(-3) = 5 - (-9) = 5 + 9 = 14
f(-2) = 5 - 3(-2) = 5 - (-6) = 5 + 6 = 11
f(-1) = 5 - 3(-1) = 5 - (-3) = 5 + 3 = 8
f(0) = 5 - 3(0) = 5 - 0 = 5
f(1) = 5 - 3(1) = 5 - 3 = 2
f(2) = 5 - 3(2) = 5 - 6 = -1
f(3) = 5 - 3(3) = 5 - 9 = -4
f(4) = 5 - 3(4) = 5 - 12 = -7