persamaan | 8-4x | = 12 persamaan | y+1 | -6 =3 persamaan | 3x-2 | = x+4

1. |8-4x| = 12  
8-4x = 12
-4x= 12-8
x = -1 
 
atau 

|8-4x|  = 12
8 + 4x = 12
4x = 12- 8
x = 1 

2. |y+1| -6 = 3  
|y+1| = 3+ 6
|y+1| =  9
(y+1)^2  = 9^2 
(y+1)^2 - 9^2 = 0 
[(y+1)-9] [(y+1) +9)]  = 0
(y+1)-9 = 0 
y+1 -9 = 0 
y-8= 0 
y = 8 

(y+1) +9) = 0
y + 1+9 = 0
y + 10 = 0
y = -10 

3.  |3x-2| = x + 4
3x-2 = x + 4
3x - x = 4 + 2
2x = 6
x = 3

atau 
3x+2 = x + 4
3x - x = 4-2
2x = 2 
x = 1