Integral x^2 sin (x^3+phi) dx

cari jawabanya di kamus

∫x² sin(x³+π) dx
=∫ x² sin(π+x³) dx
=∫ x² (-sin x³) dx
=-∫ x² sin x³ dx

misal u=x³
maka du/dx = 3x²
sehingga du/3 = x² dx

=-∫ sin u (du/3)
=-⅓ ∫ sin u du
=-⅓ (-cos u)
=⅓ cos x³ + C