Matematika

Pertanyaan

jika log 3=0,4771 dan log 5=0,6989 tentukan log 0,6,log 60,log 135,log 0,45

1 Jawaban

  • = log 0,6
    = log 6/10
    = log 3/5
    = log 3 - log 5
    = 0,4771 - 0,6989 = -0,2218

    = log 60
    = log 0,6x100
    = log 0,6 + log 100
    = -0,2218 + 2 = 1,7781

    = log 135
    = log 3x3x3x5
    = log 3^3 + log 5
    = 3log3 + log 5
    = 3x0,4771 + 0,6989
    = 1,4313 + 0,6989 = 2,1302

    = log 0,45
    = log 45/100
    = log (3x3x5) - log 100
    = log 3 + log 3 + log 5 - 2
    = 0,4771+0,4771+0,6989-2
    = -0,3469

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