jika log 3=0,4771 dan log 5=0,6989 tentukan log 0,6,log 60,log 135,log 0,45
Matematika
junisa2
Pertanyaan
jika log 3=0,4771 dan log 5=0,6989 tentukan log 0,6,log 60,log 135,log 0,45
1 Jawaban
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1. Jawaban bayura
= log 0,6
= log 6/10
= log 3/5
= log 3 - log 5
= 0,4771 - 0,6989 = -0,2218
= log 60
= log 0,6x100
= log 0,6 + log 100
= -0,2218 + 2 = 1,7781
= log 135
= log 3x3x3x5
= log 3^3 + log 5
= 3log3 + log 5
= 3x0,4771 + 0,6989
= 1,4313 + 0,6989 = 2,1302
= log 0,45
= log 45/100
= log (3x3x5) - log 100
= log 3 + log 3 + log 5 - 2
= 0,4771+0,4771+0,6989-2
= -0,3469