Deret Aritmetika 3+7+11+15+19......+U10 Dittanya: A.Suku Ke sepulub U10 B.Jumlah 10 Suku Pertama S10

a = 3
b = U2 - U1 = 7 - 3 = 4

A.

Un = a + (n-1)b
U10 = 3 + (10-1).4
U10 = 3 + 36
U10 = 39

B.

Sn = n/2 (2a + (n-1)b)
S10 = 10/2 ( 6 + 36)
S10 = 5 . 42
S10 = 210

semoga membantu

A) a = 3
b = 7 - 3 = 4

un = a + ( n - 1 ) b
u10 = 3 + (10 - 1 ) 4
u10 = 3 + (9) 4
u10 = 3 + 36 = 39

B) sn = n/2 (2a + (n-1)b)

s10= 10/2 (2(3) + (10-1)4 )
s10= 5 (6+ (9)4 )
s10= 5 (6+36)
s10= 5 (42)
s10= 210