jika P=7per6, Q=1 1per2, dan R=3per4 ,maka tentukan nilai! a. pq-qr b.(p-q)²-(q-r)²
Matematika
aulia1651
Pertanyaan
jika P=7per6, Q=1 1per2, dan R=3per4 ,maka tentukan nilai!
a. pq-qr
b.(p-q)²-(q-r)²
a. pq-qr
b.(p-q)²-(q-r)²
1 Jawaban
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1. Jawaban faizsaaatr
a. pq-qr
=(7/6x11/2)-(11/2x3/4)
=77/12-33/8
=154/24-99/24
=55/24
b. (p-q)^2-(q-r)^2
=(7/6-11/2)^2-(11/2-3/4)^2
=(7/6-33/6)^2-(22/4-3/4)^2
=-26/6^2-19/4^2
=169/9-361/16
=2704/144-3249/144
=-545/1448