MOHON BNTUANNYA? 1. (sin A/1+cos A)+(sin A/1-cos A)= 2. (cosec A-cos A) (1+cos A) =
Matematika
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Pertanyaan
MOHON BNTUANNYA?
1. (sin A/1+cos A)+(sin A/1-cos A)=
2. (cosec A-cos A) (1+cos A) =
1. (sin A/1+cos A)+(sin A/1-cos A)=
2. (cosec A-cos A) (1+cos A) =
1 Jawaban
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1. Jawaban acim
1) sin(A)/(1 + cos(A)) + sin(A)/(1-cos(A))
= (sin(A) - sin(A)cos(A) + sin(A) + sin(A)cos(A))/(1 - cos²A)
= 2sin(A)/sin²A
= 2/sin(A)
= 2 cosec(A)
2) males ngerjain, hasilnya gak enak.....