tentukan sigma nilai atas 4 k=1 (2k² + 1) - sigma nilai atas 1 k=-2 (k² + 1) tolong ya #butuhcepat

sigma

 { ₁⁴∑ 2k²  +1}  -  {₋₂¹∑ k² + 1} = p - q

p = ₁⁴∑ 2k² + 1

k =1 --> 2(1)² + 1 = 3
k= 2 --> 2(2)² +1  = 9
k = 3 --> 2(3²) + 1 = 19
k =4 --> 2(4²) + 1= 33
p = 3 +9+19+ 33 = 64

q = ₋₂¹∑(k² +1)
k = -2 --> (-2)² + 1 = 5
k = -1 --> (-1)² + 1= 2
k = 0 --> (0)² + 1 = 1
k = 1 --> (1)² +1 = 2
q = 5 +2 +1 + 2 =10

p - q = 64  -10
p - q = 54